Kill The Most Monsters
easy
On a 2D plane, we place n monsters at some integer coordinate points. Each coordinate point may have at most one monster. A monster can be removed if it shares either the same row or the same column as another monster that has not been removed. Given an array monsters of length n where monsters[i] = [xi, yi] represents the location of the ith monster, return the largest possible number of monsters that can be removed. Example 1: Input: monsters = [[0,0],[0,2],[1,1],[2,0],[2,2]] Output: 3 Explanation: One way to make 3 moves is as follows: 1. Remove monster [2,2] because it shares the same row as [2,0]. 2. Remove monster [2,0] because it shares the same column as [0,0]. 3. Remove monster [0,2] because it shares the same row as [0,0]. monsters [0,0] and [1,1] cannot be removed since they do not share a row/column with another stone still on the plane.
Constraints
1. 1 <= monsters.length <= 1000 2. 0 <= monsters[i][0],monsters[i][1] <= 1
Format
Input
Input/output is handled for you. You just need to complete the function.
Output
Input/output is handled for you. You just need to complete the function.
Example
Sample Input
6
0
0
0
1
1
0
1
2
2
1
2
2
Sample Output
5
